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12.1 Finding Limits: Numerical and Graphical Approaches

Limit notation with one-sided values, reading a limit off a graph, and estimating one from a table of inputs near the point.

Precalculus 2e, 12.1 Finding Limits: Numerical and Graphical Approaches

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30 exercises

Understanding the Limit of a Function

For the following limit, define a,f(x), a , f \left(x\right) , and L. L .

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12.1 Exercise 2

For the following limit, define a,f(x), a , f \left(x\right) , and L. L .

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12.1 Exercise 8

Numerically estimate the following limit: lim x→0 ( sin( 2 x ) ). \underset{x \rightarrow 0}{\lim} \left(\sin \left(\frac{2}{x}\right)\right) .

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12.1 Exercise 9

Explain the difference between a value at x=a x = a and the limit as x x approaches a. a .

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12.1 Exercise 11

lim x→− 2 − f(x) \underset{x \rightarrow - 2^{-}}{\lim} f \left(x\right)

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12.1 Exercise 13

lim x→−2 f(x) \underset{x \rightarrow - 2}{\lim} f \left(x\right)

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12.1 Exercise 15

lim x→ 1 − f(x) \underset{x \rightarrow 1^{-}}{\lim} f \left(x\right)

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12.1 Exercise 17

lim x→1 f(x) \underset{x \rightarrow 1}{\lim} f \left(x\right)

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12.1 Exercise 19

lim x→ 4 − f(x) \underset{x \rightarrow 4^{-}}{\lim} f \left(x\right)

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12.1 Exercise 21

lim x→4 f(x) \underset{x \rightarrow 4}{\lim} f \left(x\right)

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12.1 Exercise 23

Draw the graph of a function from the functional values and limits provided.

lim x→ 0 − f(x)=2\underset{x \rightarrow 0^{-}}{\lim} f \left(x\right) = 2, lim x→ 0 + f(x)=–3\underset{x \rightarrow 0^{+}}{\lim} f \left(x\right) = – 3, lim x→2 f(x)=2\underset{x \rightarrow 2}{\lim} f \left(x\right) = 2, f(0)=4f \left(0\right) = 4, f(2)=–1f \left(2\right) = – 1, f(–3) does not exist. f \left(– 3\right) \textrm{ }\text{does}\textrm{ }\text{not}\textrm{ }\text{exist} .

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12.1 Exercise 24

Draw the graph of a function from the functional values and limits provided.

lim x→ 2 − f(x)=0\underset{x \rightarrow 2^{-}}{\lim} f \left(x\right) = 0, lim x→ 2 + =–2\underset{x \rightarrow 2^{+}}{lim} = – 2, lim x→0 f(x)=3\underset{x \rightarrow 0}{\lim} f \left(x\right) = 3, f(2)=5f \left(2\right) = 5, f(0) f \left(0\right)

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12.1 Exercise 25

Draw the graph of a function from the functional values and limits provided.

lim x→ 2 − f(x)=2\underset{x \rightarrow 2^{-}}{\lim} f \left(x\right) = 2, lim x→ 2 + f(x)=−3\underset{x \rightarrow 2^{+}}{\lim} f \left(x\right) = - 3, lim x→0 f(x)=5\underset{x \rightarrow 0}{\lim} f \left(x\right) = 5, f(0)=1f \left(0\right) = 1, f(1)=0 f \left(1\right) = 0

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12.1 Exercise 26

Draw the graph of a function from the functional values and limits provided.

lim x→ 3 − f(x)=0\underset{x \rightarrow 3^{-}}{\lim} f \left(x\right) = 0, lim x→ 3 + f(x)=5\underset{x \rightarrow 3^{+}}{\lim} f \left(x\right) = 5, lim x→5 f(x)=0\underset{x \rightarrow 5}{\lim} f \left(x\right) = 0, f(5)=4f \left(5\right) = 4, f(3) does not exist. f \left(3\right) \textrm{ }\text{does}\textrm{ }\text{not}\textrm{ }\text{exist} .

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12.1 Exercise 27

Draw the graph of a function from the functional values and limits provided.

lim x→4 f(x)=6\underset{x \rightarrow 4}{\lim} f \left(x\right) = 6, lim x→ 6 + f(x)=−1\underset{x \rightarrow 6^{+}}{\lim} f \left(x\right) = - 1, lim x→0 f(x)=5\underset{x \rightarrow 0}{\lim} f \left(x\right) = 5, f(4)=6f \left(4\right) = 6, f(2)=6 f \left(2\right) = 6

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12.1 Exercise 28

Draw the graph of a function from the functional values and limits provided.

lim x→−3 f(x)=2\underset{x \rightarrow - 3}{\lim} f \left(x\right) = 2, lim x→ 1 + f(x)=−2\underset{x \rightarrow 1^{+}}{\lim} f \left(x\right) = - 2, lim x→3 f(x)=–4\underset{x \rightarrow 3}{\lim} f \left(x\right) = – 4, f(–3)=0f \left(– 3\right) = 0, f(0)=0 f \left(0\right) = 0

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12.1 Exercise 29

Draw the graph of a function from the functional values and limits provided.

lim x→π f(x)= π 2 \underset{x \rightarrow \pi}{\lim} f \left(x\right) = \pi^{2}, lim x→–π f(x)= π 2 \underset{x \rightarrow – \pi}{\lim} f \left(x\right) = \frac{\pi}{2}, lim x→ 1 – f(x)=0\underset{x \rightarrow 1^{–}}{\lim} f \left(x\right) = 0, f(π)= 2 f \left(\pi\right) = \sqrt{2}, f(0) does not exist. f \left(0\right) \textrm{ }\text{does}\textrm{ }\text{not}\textrm{ }\text{exist} .

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12.1 Exercise 31

Use a graphing calculator to determine the limit to 5 decimal places as x x approaches 0.

g(x)= ( 1+x ) 2 x g \left(x\right) = \left(1 + x\right)^{\frac{2}{x}}

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12.1 Exercise 33

Use a graphing calculator to determine the limit to 5 decimal places as x x approaches 0.

i(x)= ( 1+x ) 4 x i \left(x\right) = \left(1 + x\right)^{\frac{4}{x}}

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12.1 Exercise 35

Use a graphing calculator to determine the limit to 5 decimal places as x x approaches 0.

Based on the pattern you observed in the exercises above, make a conjecture as to the limit of f(x)= ( 1+x ) 6 x , f \left(x\right) = \left(1 + x\right)^{\frac{6}{x}} , g(x)= ( 1+x ) 7 x , g \left(x\right) = \left(1 + x\right)^{\frac{7}{x}} , and h(x)= ( 1+x ) n x . \text{and}\textrm{ } h \left(x\right) = \left(1 + x\right)^{\frac{n}{x}} .

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12.1 Exercise 37

Use a graphing utility to find graphical evidence to determine the left- and right-hand limits of the function given as x x approaches a. a . If the function has a limit as x x approaches a, a , state it. If not, discuss why there is no limit.

(x)={ 1 x+1 , if x=−2 (x+1) 2 , if x≠−2 a=−2 \left(x\right) = \left\{\right. \begin{matrix}\frac{1}{x + 1} , & \text{if}\textrm{ } x = - 2 \\ \left(x + 1\right)^{2} , & \text{if}\textrm{ } x \neq - 2\end{matrix} a = - 2

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12.1 Exercise 39

Use numerical evidence to determine whether the limit exists at x=a. x = a . If not, describe the behavior of the graph of the function near x=a. x = a . Round answers to two decimal places.

f(x)= x 2 −x−6 x 2 −9 ;a=3 f \left(x\right) = \frac{x^{2} - x - 6}{x^{2} - 9} ; a = 3

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12.1 Exercise 41

Use numerical evidence to determine whether the limit exists at x=a. x = a . If not, describe the behavior of the graph of the function near x=a. x = a . Round answers to two decimal places.

f(x)= x 2 –1 x 2 –3x+2 ;a=1 f \left(x\right) = \frac{x^{2} – 1}{x^{2} – 3 x + 2} ; a = 1

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12.1 Exercise 43

Use numerical evidence to determine whether the limit exists at x=a. x = a . If not, describe the behavior of the graph of the function near x=a. x = a . Round answers to two decimal places.

f(x)= 10−10 x 2 x 2 −3x+2 ;a=1 f \left(x\right) = \frac{10 - 10 x^{2}}{x^{2} - 3 x + 2} ; a = 1

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12.1 Exercise 45

Use numerical evidence to determine whether the limit exists at x=a. x = a . If not, describe the behavior of the graph of the function near x=a. x = a . Round answers to two decimal places.

f(x)= x 4 x 2 +4x+1 ;a=− 1 2 f \left(x\right) = \frac{x}{4 x^{2} + 4 x + 1} ; a = - \frac{1}{2}

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12.1 Exercise 51

Use a graphing utility to find numerical or graphical evidence to determine the left and right-hand limits of the function given as x x approaches a. a . If the function has a limit as x x approaches a, a , state it. If not, discuss why there is no limit.

lim x→0 e e − 1 x 2 \underset{x \rightarrow 0}{\lim} e^{e^{- \frac{1}{x^{2}}}}

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12.1 Exercise 53

Use a graphing utility to find numerical or graphical evidence to determine the left and right-hand limits of the function given as x x approaches a. a . If the function has a limit as x x approaches a, a , state it. If not, discuss why there is no limit.

lim x→−1 | x+1 | x+1 \underset{x \rightarrow - 1}{\lim} \frac{\left|x + 1\right|}{x + 1}

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12.1 Exercise 55

Use a graphing utility to find numerical or graphical evidence to determine the left and right-hand limits of the function given as x x approaches a. a . If the function has a limit as x x approaches a, a , state it. If not, discuss why there is no limit.

lim x→−1 1 ( x+1 ) 2 \underset{x \rightarrow - 1}{\lim} \frac{1}{\left(x + 1\right)^{2}}

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12.1 Exercise 57

Use a graphing utility to find numerical or graphical evidence to determine the left and right-hand limits of the function given as x x approaches a. a . If the function has a limit as x x approaches a, a , state it. If not, discuss why there is no limit.

lim x→0 5 1− e 2 x \underset{x \rightarrow 0}{\lim} \frac{5}{1 - e^{\frac{2}{x}}}

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12.1 Exercise 59

According to the Theory of Relativity, the mass m m of a particle depends on its velocity v v. That is

where m o m_{o} is the mass when the particle is at rest and c c is the speed of light. Find the limit of the mass, m, m , as v v approaches c − . c^{-} .

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Adapted from College Algebra © 2021 Rice University. Licensed under CC BY 4.0. Sources: College Algebra 2e, Algebra and Trigonometry 2e, Precalculus 2e, College Algebra with Corequisite Support 2e. Imported at revision 4922e46.