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Mathematical Induction

Proving a claim for every integer past a base case through the inductive step, and strong induction when many earlier cases are needed at once.

Discrete Math for Shockers, Mathematical Induction

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13 exercises

Exercise 2

Prove that 1+3+5+⋯+(2n−1)=n21 + 3 + 5 + \cdots + (2n-1) = n^2 for all n≥1n \ge 1.

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Exercise 3

Prove that 2n<n!2^n \lt n! for all n≥4n \ge 4. (Recall, n!=1⋅2⋅3⋅⋯⋅nn! = 1\cdot 2 \cdot 3 \cdot \cdots\cdot n.)

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Exercise 4

Prove that the sum of nn squares can be found as follows

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Exercise 5

What is wrong with the following “proof” of the “fact” that n+3=n+7n+3 = n+7 for all values of nn (besides of course that the thing it is claiming to prove is false)?

Let P(n)P(n) be the statement that n+3=n+7n + 3 = n + 7. We will prove that P(n)P(n) is true for all n∈Nn \in \N. Assume, for induction that P(k)P(k) is true. That is, k+3=k+7k+3 = k+7. We must show that P(k+1)P(k+1) is true. Now since k+3=k+7k + 3 = k + 7, add 1 to both sides. This gives k+3+1=k+7+1k + 3 + 1 = k + 7 + 1. Regrouping (k+1)+3=(k+1)+7(k+1) + 3 = (k+1) + 7. But this is simply P(k+1)P(k+1). Thus by the prin…

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Exercise 6

The proof in the previous problem does not work. But if we modify the “fact,” we can get a working proof. Prove that n+3<n+7n + 3 \lt n + 7 for all values of n∈Nn \in \N. You can do this proof with algebra (without induction), but the goal of this exercise is to write out a valid induction proof.

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Exercise 9

Now give a valid proof (by induction, even though you might be able to do so without using induction) of the statement, “for all n∈Nn \in \N, the number n2+nn^2 + n is even.”

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Exercise 10

Use induction to prove that if nn people all shake hands with each other, that the total number of handshakes is n(n−1)2\frac{n(n-1)}{2}.

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Exercise 11

Use the product rule for logarithms (log⁡(ab)=log⁡(a)+log⁡(b)\log(ab) = \log(a) + \log(b)) to prove, by induction on nn, that log⁡(an)=nlog⁡(a)\log(a^n) = n \log(a), for all natural numbers n≥2n \ge 2.

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Exercise 13

Recall that FnF_n is the nnth Fibonacci number defined in this example.

Prove, by mathematical induction, that F0+F1+F2+⋯+Fn=Fn+2−1F_0 + F_1 + F_2 + \cdots + F_{n} = F_{n+2} - 1.

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Exercise 14

Prove that F0+F2+F4+⋯+F2n=F2n+1−1F_0 + F_2 + F_4 + \cdots + F_{2n} = F_{2n+1} - 1 where FnF_n is the nnth Fibonacci number.

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Exercise 15

Prove, using strong induction, that every natural number is either a Fibonacci number or can be written as the sum of distinct Fibonacci numbers.

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Exercise 16

Prove, by mathematical induction, that F1+F3+F5+⋯+F2n−1=F2nF_1 + F_3 + F_5 + \dots + F_{2n -1} = F_{2n}, where FnF_n is the nnth Fibonacci number.

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Exercise 19

Prove that 6 divides 7n−17^n - 1 for all n∈Nn \in \N.

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Adapted from Discrete Math for Shockers © 2021 John Hammond. Licensed under CC BY-SA 4.0. Source: Discrete Math for Shockers. Imported at revision 2538beb.