Mathematical Induction
Proving a claim for every integer past a base case through the inductive step, and strong induction when many earlier cases are needed at once.
13 exercises
Exercise 2
Prove that for all .
Exercise 3
Prove that for all . (Recall, .)
Exercise 4
Prove that the sum of squares can be found as follows
Exercise 5
What is wrong with the following “proof” of the “fact” that for all values of (besides of course that the thing it is claiming to prove is false)?
Let be the statement that . We will prove that is true for all . Assume, for induction that is true. That is, . We must show that is true. Now since , add 1 to both sides. This gives . Regrouping . But this is simply . Thus by the prin…
Exercise 6
The proof in the previous problem does not work. But if we modify the “fact,” we can get a working proof. Prove that for all values of . You can do this proof with algebra (without induction), but the goal of this exercise is to write out a valid induction proof.
Exercise 9
Now give a valid proof (by induction, even though you might be able to do so without using induction) of the statement, “for all , the number is even.”
Exercise 10
Use induction to prove that if people all shake hands with each other, that the total number of handshakes is .
Exercise 11
Use the product rule for logarithms () to prove, by induction on , that , for all natural numbers .
Exercise 13
Recall that is the th Fibonacci number defined in this example.
Prove, by mathematical induction, that .
Exercise 14
Prove that where is the th Fibonacci number.
Exercise 15
Prove, using strong induction, that every natural number is either a Fibonacci number or can be written as the sum of distinct Fibonacci numbers.
Exercise 16
Prove, by mathematical induction, that , where is the th Fibonacci number.
Exercise 19
Prove that 6 divides for all .
Adapted from Discrete Math for Shockers © 2021 John Hammond. Licensed under CC BY-SA 4.0. Source: Discrete Math for Shockers. Imported at revision 2538beb.