Back to Intermediate Algebra 2e

8.6 Solve Radical Equations

Isolating a radical and raising both sides to a power, why that step manufactures extraneous roots, and equations holding two separate radicals.

Intermediate Algebra 2e, 8.6 Solve Radical Equations

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60 exercises

8.6 Exercise 1

Before you get started, take this readiness quiz.

Simplify: (y−3)2.\left(y - 3\right)^{2} .
If you missed this problem, review the reference.

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8.6 Exercise 2

Solve: 2x−5=0.2 x - 5 = 0 .
If you missed this problem, review the reference.

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8.6 Exercise 3

Solve n2−6n+8=0.n^{2} - 6 n + 8 = 0 .
If you missed this problem, review the reference.

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8.6 Exercise 5

Solve: 3m+2−5=0.\sqrt{3 m + 2} - 5 = 0 .

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8.6 Exercise 6

Solve: 10z+1−2=0.\sqrt{10 z + 1} - 2 = 0 .

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8.6 Exercise 8

Solve: 2r−3+5=0.\sqrt{2 r - 3} + 5 = 0 .

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8.6 Exercise 9

Solve: 7s−3+2=0.\sqrt{7 s - 3} + 2 = 0 .

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8.6 Exercise 11

Solve: x−2+2=x.\sqrt{x - 2} + 2 = x .

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8.6 Exercise 12

Solve: y−5+5=y.\sqrt{y - 5} + 5 = y .

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8.6 Exercise 14

Solve: 4x−33+8=5\sqrt[3]{4 x - 3} + 8 = 5

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8.6 Exercise 15

Solve: 6x−103+1=−3\sqrt[3]{6 x - 10} + 1 = −3

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8.6 Exercise 17

Solve: (9x+9)14−2=1.\left(9 x + 9\right)^{\frac{1}{4}} - 2 = 1 .

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8.6 Exercise 18

Solve: (4x−8)14+5=7.\left(4 x - 8\right)^{\frac{1}{4}} + 5 = 7 .

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8.6 Exercise 20

Solve: m+9−m+3=0.\sqrt{m + 9} - m + 3 = 0 .

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8.6 Exercise 21

Solve: n+1−n+1=0.\sqrt{n + 1} - n + 1 = 0 .

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8.6 Exercise 23

Solve: 24a+4−16=16.2 \sqrt{4 a + 4} - 16 = 16 .

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8.6 Exercise 24

Solve: 32b+3−25=50.3 \sqrt{2 b + 3} - 25 = 50 .

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8.6 Exercise 25

Solve: 4x−33=3x+23.\sqrt[3]{4 x - 3} = \sqrt[3]{3 x + 2} .

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8.6 Exercise 26

Solve: 5x−43=2x+53.\sqrt[3]{5 x - 4} = \sqrt[3]{2 x + 5} .

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8.6 Exercise 27

Solve: 7x+13=2x−53.\sqrt[3]{7 x + 1} = \sqrt[3]{2 x - 5} .

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8.6 Exercise 29

Solve: 3−x=x−3.3 - \sqrt{x} = \sqrt{x - 3} .

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8.6 Exercise 30

Solve: x+2=x+16.\sqrt{x} + 2 = \sqrt{x + 16} .

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8.6 Exercise 32

Solve: x−1+2=2x+6\sqrt{x - 1} + 2 = \sqrt{2 x + 6}

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8.6 Exercise 33

Solve: x+2=3x+4\sqrt{x} + 2 = \sqrt{3 x + 4}

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8.6 Exercise 35

A helicopter dropped a rescue package from a height of 1,296 feet. Use the formula t=h4t = \frac{\sqrt{h}}{4} to find how many seconds it took for the package to reach the ground.

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8.6 Exercise 36

A window washer dropped a squeegee from a platform 196 feet above the sidewalk Use the formula t=h4t = \frac{\sqrt{h}}{4} to find how many seconds it took for the squeegee to reach the sidewalk.

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8.6 Exercise 38

An accident investigator measured the skid marks of the car. The length of the skid marks was 76 feet. Use the formula s=24ds = \sqrt{24 d} to find the speed of the car before the brakes were applied. Round your answer to the nearest tenth.

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8.6 Exercise 39

The skid marks of a vehicle involved in an accident were 122 feet long. Use the formula s=24ds = \sqrt{24 d} to find the speed of the vehicle before the brakes were applied. Round your answer to the nearest tenth.

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8.6 Exercise 40

Solve.

5x−6=8\sqrt{5 x - 6} = 8

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8.6 Exercise 42

Solve.

5x+1=−3\sqrt{5 x + 1} = −3

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8.6 Exercise 44

Solve.

2x3=−2\sqrt[3]{2 x} = −2

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8.6 Exercise 46

Solve.

2m−3−5=0\sqrt{2 m - 3} - 5 = 0

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8.6 Exercise 48

Solve.

6v−2−10=0\sqrt{6 v - 2} - 10 = 0

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8.6 Exercise 50

Solve.

4m+2+2=6\sqrt{4 m + 2} + 2 = 6

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8.6 Exercise 52

Solve.

2u−3+2=0\sqrt{2 u - 3} + 2 = 0

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8.6 Exercise 54

Solve.

u−3+3=u\sqrt{u - 3} + 3 = u

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8.6 Exercise 56

Solve.

r−1=r−1\sqrt{r - 1} = r - 1

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8.6 Exercise 58

Solve.

6x+43=4\sqrt[3]{6 x + 4} = 4

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8.6 Exercise 60

Solve.

4x+53−2=−5\sqrt[3]{4 x + 5} - 2 = −5

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8.6 Exercise 62

Solve.

(6x+1)12−3=4\left(6 x + 1\right)^{\frac{1}{2}} - 3 = 4

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8.6 Exercise 64

Solve.

(8x+5)13+2=−1\left(8 x + 5\right)^{\frac{1}{3}} + 2 = −1

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8.6 Exercise 66

Solve.

(12x−3)14−5=−2\left(12 x - 3\right)^{\frac{1}{4}} - 5 = −2

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8.6 Exercise 68

Solve.

x+1−x+1=0\sqrt{x + 1} - x + 1 = 0

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8.6 Exercise 70

Solve.

z+100−z=−10\sqrt{z + 100} - z = −10

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8.6 Exercise 72

Solve.

32x−3−20=73 \sqrt{2 x - 3} - 20 = 7

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8.6 Exercise 74

Solve.

28r+1−8=22 \sqrt{8 r + 1} - 8 = 2

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8.6 Exercise 76

Solve.

3u+7=5u+1\sqrt{3 u + 7} = \sqrt{5 u + 1}

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8.6 Exercise 78

Solve.

8+2r=3r+10\sqrt{8 + 2 r} = \sqrt{3 r + 10}

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8.6 Exercise 80

Solve.

5x−13=x+33\sqrt[3]{5 x - 1} = \sqrt[3]{x + 3}

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8.6 Exercise 82

Solve.

2x2+9x−183=x2+3x−23\sqrt[3]{2 x^{2} + 9 x - 18} = \sqrt[3]{x^{2} + 3 x - 2}

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8.6 Exercise 84

Solve.

a+2=a+4\sqrt{a} + 2 = \sqrt{a + 4}

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8.6 Exercise 86

Solve.

u+1=u+4\sqrt{u} + 1 = \sqrt{u + 4}

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8.6 Exercise 88

Solve.

a+5−a=1\sqrt{a + 5} - \sqrt{a} = 1

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8.6 Exercise 90

Solve.

2x+1=1+x\sqrt{2 x + 1} = 1 + \sqrt{x}

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8.6 Exercise 92

Solve.

2x−1−x−1=1\sqrt{2 x - 1} - \sqrt{x - 1} = 1

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8.6 Exercise 94

Solve.

x+7−x−5=2\sqrt{x + 7} - \sqrt{x - 5} = 2

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8.6 Exercise 96

Solve. Round approximations to one decimal place.

Landscaping Reed wants to have a square garden plot in his backyard. He has enough compost to cover an area of 75 square feet. Use the formula s=As = \sqrt{A} to find the length of each side of his garden. Round your answer to the nearest tenth of a foot.

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8.6 Exercise 98

Solve. Round approximations to one decimal place.

Gravity A hang glider dropped his cell phone from a height of 350 feet. Use the formula t=h4t = \frac{\sqrt{h}}{4} to find how many seconds it took for the cell phone to reach the ground.

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8.6 Exercise 100

Solve. Round approximations to one decimal place.

Accident investigation The skid marks for a car involved in an accident measured 216 feet. Use the formula s=24ds = \sqrt{24 d} to find the speed of the car before the brakes were applied. Round your answer to the nearest tenth.

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8.6 Exercise 102

Explain why an equation of the form x+1=0\sqrt{x} + 1 = 0 has no solution.

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Adapted from Intermediate Algebra 2e © 2020 Rice University. Licensed under CC BY 4.0. Source: Intermediate Algebra 2e. Imported at revision 77a933c.