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Basis and dimension

True-or-false reasoning about how many vectors in R^5 can be linearly independent or spanning, with a basis computation over the integers modulo 5.

Matrix Theory and Linear Algebra, Basis and dimension

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3 exercises

Exercise 5.4.11

In this exercise, we use scalars from the field Z5\mathbb{Z}_{5} of integers modulo 55 instead of real numbers (see Section an exercise given elsewhere in the book, “Fields”). Find a basis and the dimension of each of the following subspaces of (Z5)n(\mathbb{Z}_{5})^{n}.

  1. V1=span⁡{[2314], [1432], [4123], [2210]}V_{1}=\operatorname{span}\left\{\left[\begin{array}{r}2\\ 3\\ 1\\ 4\end{array}\right],~{}\left[\begin{array}{r}1\\ 4\\ 3\\ 2\end{array}\right],~{}\left[\begin{array}{r}4\\ 1\\ 2\\ 3\end{array}\right],~{}\left[\begin{array}{r}2\\ 2\\ 1\\ 0\end{array}\right]\right\}.

  2. V2={[uvw] ∣ 2u+v=0 and u+4w=0}.V_{2}=\left\{\left.\left[\begin{array}{c}u\\ v\\ w\end{array}\right]~{}\right|~{}\text{$2u+v=0$ and $u+4w=0$}\right\}.

  3. V3={[uvw] ∣ u+2v+3w=0}.V_{3}=\left\{\left.\left[\begin{array}{c}u\\ v\\ w\end{array}\right]~{}\right|~{}\text{$u+2v+3w=0$}\right\}.

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Exercise 5.4.14

True or false? Explain.

  1. Every set of 55 vectors in R5\mathbb{R}^{5} is linearly independent.

  2. Every set of 44 vectors in R5\mathbb{R}^{5} is linearly independent.

  3. Every set of 66 vectors in R5\mathbb{R}^{5} is linearly dependent.

  4. No set of 44 vectors spans R5\mathbb{R}^{5}.

  5. Every linearly independent set of 55 vectors in R5\mathbb{R}^{5} is a basis of R5\mathbb{R}^{5}.

  6. Every linearly independent set of 44 vectors in R5\mathbb{R}^{5} is a basis of R5\mathbb{R}^{5}.

  7. Some linearly independent set of 44 vectors i…

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Exercise 5.4.15

If you have 66 vectors in R5\mathbb{R}^{5}, is it possible they are linearly independent? Explain.

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Adapted from Matrix Theory and Linear Algebra © 2017–2026 Peter Selinger, Lyryx Learning, and Ken Kuttler. Licensed under CC BY 4.0. Source: Matrix Theory and Linear Algebra. Imported at revision d74bc3a.