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2.3 Algebra of Vectors

Adding and subtracting analytically component by component, and solving vector equations for an unknown vector instead of drawing it.

University Physics Volume 1, 2.3 Algebra of Vectors

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11 exercises

2.3 Exercise 1

Three displacement vectors A→\overset{\rightarrow}{A}, B→\overset{\rightarrow}{B}, and F→\overset{\rightarrow}{F} (the reference) are specified by their magnitudes A = 10.00, B = 7.00, and F = 20.00, respectively, and by their respective direction angles with the horizontal direction α=35°\alpha = 35 °, β=−110°\beta = −110 °, and φ=110°\varphi = 110 °. The physical units of the magnitudes are centimeters. Use the analytical method to find vector G→=A→+2B→−F→\overset{\rightarrow}{G} = \overset{\rightarrow}{A} + 2 \overset{\rightarrow}{B} - \overset{\rightarrow}{F}. Verify that
G = 28.15 cm and that θG=−68.65°\theta_{G} = −68.65 °.

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2.3 Exercise 2

Suppose that Balto in the example leaves the game to attend to more important matters, but Astro, Clifford, and Dug continue playing. Astro and Clifford's pull on the toy does not change, but Dug runs around and bites on the toy in a different place. With how big a force and in what direction must Dug pull on the toy now to balance out the combined pulls from Clifford and Astro? Illustrate this s…

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2.3 Exercise 3

Verify that vector v^\hat{v} obtained in the example is indeed a unit vector by computing its magnitude. If the convoy in the example was moving across a desert flatland—that is, if the third component of its velocity was zero—what is the unit vector of its direction of motion? Which geographic direction does it represent?

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2.3 Exercise 4

For vectors B→=−i^−4j^\overset{\rightarrow}{B} = − \hat{i} - 4 \hat{j} and A→=−3i^−2j^\overset{\rightarrow}{A} = −3 \hat{i} - 2 \hat{j}, calculate (a) A→+B→\overset{\rightarrow}{A} + \overset{\rightarrow}{B} and its magnitude and direction angle, and (b) A→−B→\overset{\rightarrow}{A} - \overset{\rightarrow}{B} and its magnitude and direction angle.

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2.3 Exercise 6

Given two displacement vectors A→=(3.00i^−4.00j^+4.00k^)m\overset{\rightarrow}{A} = \left(3.00 \hat{i} - 4.00 \hat{j} + 4.00 \hat{k}\right) \text{m} and B→=(2.00i^+3.00j^−7.00k^)m\overset{\rightarrow}{B} = \left(2.00 \hat{i} + 3.00 \hat{j} - 7.00 \hat{k}\right) \text{m}, find the displacements and their magnitudes for (a) C→=A→+B→\overset{\rightarrow}{C} = \overset{\rightarrow}{A} + \overset{\rightarrow}{B} and (b) D→=2A→−B→\overset{\rightarrow}{D} = 2 \overset{\rightarrow}{A} - \overset{\rightarrow}{B}.

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2.3 Exercise 8

In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the day, and she is blown along the following straight lines: 2.50 km and 45.0°45.0 ° north of west, then 4.70 km and 60.0°60.0 ° south of east, then 1.30 km and 25.0°25.0 ° south of west, then 5.10 km due east, then 1.70 km and 5.00°5.00 ° east of north, then 7.20 km and 55.0°55.0 ° south of west, and finally 2.80 km and 10.0°10.0 ° n…

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2.3 Exercise 10

Given the vectors in the preceding figure, find vector R→\overset{\rightarrow}{R} that solves equations (a) D→+R→=F→\overset{\rightarrow}{D} + \overset{\rightarrow}{R} = \overset{\rightarrow}{F} and (b) C→−2D→+5R→=3F→\overset{\rightarrow}{C} - 2 \overset{\rightarrow}{D} + 5 \overset{\rightarrow}{R} = 3 \overset{\rightarrow}{F}. Assume the +x-axis is horizontal to the right.

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2.3 Exercise 12

An adventurous dog strays from home, runs three blocks east, two blocks north, and one block east, one block north, and two blocks west. Assuming that each block is about a 100 yd, use the analytical method to find the dog’s net displacement vector, its magnitude, and its direction. Assume the +x-axis is to the east. How would your answer be affected if each block was about 100 m?

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2.3 Exercise 14

Given the displacement vector D→=(3i^−4j^)m,\overset{\rightarrow}{D} = \left(3 \hat{i} - 4 \hat{j}\right) \text{m}, find the displacement vector R→\overset{\rightarrow}{R} so that D→+R→=−4Dj^\overset{\rightarrow}{D} + \overset{\rightarrow}{R} = −4 D \hat{j}.

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2.3 Exercise 16

At one point in space, the direction of the electric field vector is given in the Cartesian system by the unit vector E^=1/5i^−2/5j^\hat{E} = 1 / \sqrt{5} \hat{i} - 2 / \sqrt{5} \hat{j}. If the magnitude of the electric field vector is E = 400.0 V/m, what are the scalar components ExE_{x}, EyE_{y}, and EzE_{z} of the electric field vector E→\overset{\rightarrow}{E} at this point? What is the direction angle θE\theta_{E} of the electric field vector at this point?

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2.3 Exercise 18

In the control tower at a regional airport, an air traffic controller monitors two aircraft that travel in straight paths directly away from the control tower. One plane is a cargo carrier Boeing 747 climbing at 10°10 ° above the horizontal, and moving 30°30 ° north of west. At some moment in time, the controller notes that the Boeing is at an altitude of 2500 m and the DC-3 is at an altitude of 3000 m. The…

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Adapted from University Physics Volume 1 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 1. Imported at revision db44eb9.