6.2 Explaining Gauss’s Law

Why flux through any closed surface depends only on the charge inside and not on its position, and the symmetry needed for the relation to be usable.

University Physics Volume 2, 6.2 Explaining Gauss’s Law

Status

FlagsLoading your progress…

7 exercises

6.2 Exercise 2

Two concentric spherical surfaces enclose a point charge q. The radius of the outer sphere is twice that of the inner one. Compare the electric fluxes crossing the two surfaces.

2.5

6.2 Exercise 4

(a) If the electric flux through a closed surface is zero, is the electric field necessarily zero at all points on the surface? (b) What is the net charge inside the surface?

2.5

6.2 Exercise 6

Discuss the similarities and differences between the gravitational field of a point mass m and the electric field of a point charge q.

2.5

6.2 Exercise 8

Is the term $\overset{\rightarrow}{E}$ in Gauss’s law the electric field produced by just the charge inside the Gaussian surface?

2.5

6.2 Exercise 13

A point charge of $10 \mu \text{C}$ is at an unspecified location inside a cube of side 2 cm. Find the net electric flux though the surfaces of the cube.

2.5

6.2 Exercise 17

The electric flux through a spherical surface is $4.0 \times 10^{4} \text{N} \cdot \text{m}^{2} /\text{C} .$ What is the net charge enclosed by the surface?

2.5

6.2 Exercise 19

Repeat the previous problem, assuming that the electric field is directed along a body diagonal of the cube.

2.5