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Exercise 10

Avg difficulty 2.5

For a certain function ff, its derivative is known to be f′(x)=(x−1)e−x2f'(x) = (x-1)e^{-x^2}. Note that you do not know a formula for y=f(x)y = f(x).

  1. At what xx-value(s) is f′(x)=0f'(x) = 0? Justify your answer algebraically, but include a graph of f′f' to support your conclusion.

  2. Reasoning graphically, for what intervals of xx-values is f′′(x)>0f''(x) \gt 0? What does this tell you about the behavior of the original function ff? Explain.

  3. Assuming that f(2)=−3f(2) = -3, estimate the value of f(1.88)f(1.88) by finding and using the tangent line approximation to ff at x=2x=2. Is your estimate larger or smaller than the true value of f(1.88)f(1.88)? Justify your answer.

Boelkins, Active Calculus, §1.8 The tangent line approximation, Exercise 10

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.