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Exercise 9

Avg difficulty 2.5

An object moving along a straight line path has a differentiable position function y=s(t)y = s(t); s(t)s(t) measures the object's position relative to the origin at time tt. It is known that at time t=9t = 9 seconds, the object's position is s(9)=4s(9) = 4 feet (i.e., 4 feet to the right of the origin). Furthermore, the object's instantaneous velocity at t=9t = 9 is −1.2-1.2 feet per second, and its acceleration at the same instant is 0.080.08 feet per second per second.

  1. Use local linearity to estimate the position of the object at t=9.34t = 9.34.

  2. Is your estimate likely too large or too small? Why?

  3. In everyday language, describe the behavior of the moving object at t=9t = 9. Is it moving toward the origin or away from it? Is its velocity increasing or decreasing?

Boelkins, Active Calculus, §1.8 The tangent line approximation, Exercise 9

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.