Back to Elementary derivative rules

Exercise 11

Avg difficulty 2.5

Let f(x)=axf(x) = a^x. The goal of this problem is to explore how the value of aa affects the derivative of f(x)f(x), without assuming we know the rule for ddx[ax]\frac{d}{dx}[a^x] that we have stated and used in earlier work in this section.

  1. Use the limit definition of the derivative to show that f′(x)=lim⁡h→0ax⋅ah−axh\begin{gathered} f'(x) = \lim_{h \to 0} \frac{a^x \cdot a^h - a^x}{h} \end{gathered}.

  2. Explain why it is also true that f′(x)=ax⋅lim⁡h→0ah−1h\begin{gathered} f'(x) = a^x \cdot \lim_{h \to 0} \frac{a^h - 1}{h} \end{gathered}.

  3. Use computing technology and small values of hh to estimate the value of L=lim⁡h→0ah−1h\begin{gathered} L = \lim_{h \to 0} \frac{a^h - 1}{h} \end{gathered} when a=2a = 2. Do likewise when a=3a = 3.

  4. Note that it would be ideal if the value of the limit LL was 11, for then ff would be a particularly special function: its derivative would be simply axa^x, which would mean that its derivative is itself. By experimenting with different values of aa between 22 and 33, try to find a value for aa for which L=lim⁡h→0ah−1h=1\begin{gathered} L = \lim_{h \to 0} \frac{a^h - 1}{h} = 1 \end{gathered}.

  5. Compute ln⁡(2)\ln(2) and ln⁡(3)\ln(3). What does your work in (b) and (c) suggest is true about ddx[2x]\frac{d}{dx}[2^x] and ddx[3x]\frac{d}{dx}[3^x]?

  6. How do your investigations in (d) lead to a particularly important fact about the function f(x)=exf(x) = e^x?

Boelkins, Active Calculus, §2.1 Elementary derivative rules, Exercise 11

AI Tutor

Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.