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Activity 2.4.2

Avg difficulty 2.5

Let h(x)=sec⁡(x)h(x) = \sec(x) and recall that sec⁡(x)=1cos⁡(x)\sec(x) = \frac{1}{\cos(x)}.

  1. What is the domain of hh?

  2. Use the quotient rule to develop a formula for h′(x)h'(x) that is expressed completely in terms of sin⁡(x)\sin(x) and cos⁡(x)\cos(x).

  3. How can you use other relationships among trigonometric functions to write h′(x)h'(x) only in terms of tan⁡(x)\tan(x) and sec⁡(x)\sec(x)?

  4. What is the domain of h′h'? How does this compare to the domain of hh?

Boelkins, Active Calculus, §2.4 Derivatives of other trigonometric functions, Activity 2.4.2

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.