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Derivatives of other trigonometric functions

Tangent, cotangent, secant, and cosecant derivatives obtained by quotient-rule work on sine and cosine, then used inside larger expressions.

Active Calculus, Derivatives of other trigonometric functions

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6 exercises

Activity 2.4.2

Let h(x)=sec⁡(x)h(x) = \sec(x) and recall that sec⁡(x)=1cos⁡(x)\sec(x) = \frac{1}{\cos(x)}.

  1. What is the domain of hh?

  2. Use the quotient rule to develop a formula for h′(x)h'(x) that is expressed completely in terms of sin⁡(x)\sin(x) and cos⁡(x)\cos(x).

  3. How can you use other relationships among trigonometric functions to write h′(x)h'(x) only in terms of tan⁡(x)\tan(x) and sec⁡(x)\sec(x)?

  4. What is the domain of h′h'? How does this compare to the domain of hh?

2.5

Activity 2.4.3

Let p(x)=csc⁡(x)p(x) = \csc(x) and recall that csc⁡(x)=1sin⁡(x)\csc(x) = \frac{1}{\sin(x)}.

  1. What is the domain of pp?

  2. Use the quotient rule to develop a formula for p′(x)p'(x) that is expressed completely in terms of sin⁡(x)\sin(x) and cos⁡(x)\cos(x).

  3. How can you use other relationships among trigonometric functions to write p′(x)p'(x) only in terms of cot⁡(x)\cot(x) and csc⁡(x)\csc(x)?

  4. What is the domain of p′p'? How does this compare to the domain of pp?

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Activity 2.4.4

Respond to each of the following prompts. Where a derivative is requested, be sure to label the derivative function with its name using proper notation.

  1. Let f(x)=5sec⁡(x)−2csc⁡(x)f(x) = 5 \sec(x) - 2\csc(x). Find the slope of the tangent line to ff at the point where x=π3x =\frac{\pi}{3}.

  2. Let p(z)=z2sec⁡(z)−zcot⁡(z)p(z) = z^2\sec(z) - z\cot(z). Find the instantaneous rate of change of pp at the point where z=π4z = \frac{\pi}{4}.

  3. Let h(t)=tan⁡(t)t2+1−2etcos⁡(t)h(t) = \displaystyle \frac{\tan (t)}{t^2+1} - 2e^t \cos(t). Find h′(t)h'(t).

  4. Let g(r)=rsec⁡(r)5rg(r) = \displaystyle \frac{r \sec(r) }{5^r}. Find g′(r)g'(r).

  5. When a mass hangs from a spring and is set in motion, the object's position oscil…

2.5

Exercise 8

An object moving vertically has its height at time tt (measured in feet, with time in seconds) given by the function h(t)=3+2cos⁡(t)1.2th(t) = 3 + \frac{2\cos(t)}{1.2^t}.

  1. What is the object's instantaneous velocity when t=2t =2?

  2. What is the object's acceleration at the instant t=2t = 2?

  3. Describe in everyday language the behavior of the object at the instant t=2t = 2.

2.5

Exercise 9

Let f(x)=sin⁡(x)cot⁡(x)f(x) = \sin(x) \cot(x).

  1. Use the product rule to find f′(x)f'(x).

  2. True or false: for all real numbers xx, f(x)=cos⁡(x)f(x) = \cos(x).

  3. Explain why the function that you found in (a) is almost the opposite of the sine function, but not quite. (Hint: convert all of the trigonometric functions in (a) to sines and cosines, and work to simplify. Think carefully about the domain of ff and the domain of f′f'.)

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Exercise 10

Let p(z)p(z) be given by the rule .

  1. Determine p′(z)p'(z).

  2. Find an equation for the tangent line to pp at the point where z=0z = 0.

  3. At z=0z = 0, is pp increasing, decreasing, or neither? Why?

2.5

Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.