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Exercise 8

Avg difficulty 2.5

An object moving vertically has its height at time tt (measured in feet, with time in seconds) given by the function h(t)=3+2cos⁡(t)1.2th(t) = 3 + \frac{2\cos(t)}{1.2^t}.

  1. What is the object's instantaneous velocity when t=2t =2?

  2. What is the object's acceleration at the instant t=2t = 2?

  3. Describe in everyday language the behavior of the object at the instant t=2t = 2.

Boelkins, Active Calculus, §2.4 Derivatives of other trigonometric functions, Exercise 8

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.