Back to Integration by substitution

Exercise 13

Avg difficulty 2.5

Consider the indefinite integral ∫sin⁡3(x) dx\int \sin^3(x) \, dx.

  1. Explain why the substitution u=sin⁡(x)u = \sin(x) will not work to help evaluate the given integral.

  2. Recall the Fundamental Trigonometric Identity, which states that sin⁡2(x)+cos⁡2(x)=1\sin^2(x) + \cos^2(x) = 1. By observing that sin⁡3(x)=sin⁡(x)⋅sin⁡2(x)\sin^3(x) = \sin(x) \cdot \sin^2(x), use the Fundamental Trigonometric Identity to rewrite the integrand as the product of sin⁡(x)\sin(x) with another function.

  3. Explain why the substitution u=cos⁡(x)u = \cos(x) now provides a possible way to evaluate the integral in (b).

  4. Use your work in (a)-(c) to evaluate the indefinite integral ∫sin⁡3(x) dx\int \sin^3(x) \, dx.

  5. Use a similar approach to evaluate ∫cos⁡3(x) dx\int \cos^3(x) \, dx.

Boelkins, Active Calculus, §5.3 Integration by substitution, Exercise 13

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.