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Integration by substitution

Reversing the chain rule by finding a function-derivative pair, substituting u, and indefinite-integral notation for a whole family of antiderivatives.

Active Calculus, Integration by substitution

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6 exercises

Activity 5.3.2

Evaluate each of the following indefinite integrals. Check each antiderivative that you find by differentiating.

  1. ∫sin⁡(8−3x) dx\displaystyle \int \sin(8-3x) \, dx

  2. ∫sec⁡2(4x) dx\displaystyle \int \sec^2 (4x) \, dx

  3. ∫111x−9 dx\displaystyle \int \frac{1}{11x - 9} \, dx

  4. ∫csc⁡(2x+1)cot⁡(2x+1) dx\displaystyle \int \csc(2x+1) \cot(2x+1) \, dx

  5. ∫11−16x2 dx\displaystyle \int \frac{1}{\sqrt{1-16x^2}}\, dx

  6. ∫5−x dx\displaystyle \int 5^{-x}\, dx

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Activity 5.3.3

Evaluate each of the following indefinite integrals by using these steps:

  • Find two functions within the integrand that form (up to a possible missing constant) a function-derivative pair;

  • Make a substitution and convert the integral to one involving uu and dudu;

  • Evaluate the new integral in uu;

  • Convert the resulting function of uu back to a function of xx by using your earlier substitution;

  • Check your work by…

2.5

Activity 5.3.4

Evaluate each of the following definite integrals exactly through an appropriate uu-substitution.

  1. ∫12x1+4x2 dx\displaystyle \int_1^2 \frac{x}{1 + 4x^2} \, dx

  2. ∫01e−x(2e−x+3)9 dx\displaystyle \int_0^1 e^{-x} (2e^{-x}+3)^{9} \, dx

  3. ∫2/π4/πcos⁡(1x)x2 dx\displaystyle \int_{2/\pi}^{4/\pi} \frac{\cos\left(\frac{1}{x}\right)}{x^{2}} \,dx

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Exercise 11

This problem centers on finding antiderivatives for the basic trigonometric functions other than sin⁡(x)\sin(x) and cos⁡(x)\cos(x).

  1. Consider the indefinite integral ∫tan⁡(x) dx\int \tan(x) \, dx. By rewriting the integrand as tan⁡(x)=sin⁡(x)cos⁡(x)\tan(x) = \frac{\sin(x)}{\cos(x)} and identifying an appropriate function-derivative pair, make a uu-substitution and hence evaluate ∫tan⁡(x) dx\int \tan(x) \, dx.

  2. In a similar way, evaluate ∫cot⁡(x) dx\int \cot(x) \, dx.

  3. Consider the indefinite integral . Evaluate this integral using the substitution u=sec⁡(x)+tan⁡(x)u = \sec(x) + \tan(x).

  4. Simplify the in…

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Exercise 12

Consider the indefinite integral ∫xx−1 dx\int x \sqrt{x-1} \, dx.

  1. At first glance, this integrand may not seem suited to substitution due to the presence of xx in separate locations in the integrand. Nonetheless, using the composite function x−1\sqrt{x-1} as a guide, let u=x−1u = x-1. Determine expressions for both xx and dxdx in terms of uu.

  2. Convert the given integral in xx to a new integral in uu.

  3. Evaluate the integral in (b) by noting that u=u1/2\sqrt{u} = u^{1/2} and observing t…

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Exercise 13

Consider the indefinite integral ∫sin⁡3(x) dx\int \sin^3(x) \, dx.

  1. Explain why the substitution u=sin⁡(x)u = \sin(x) will not work to help evaluate the given integral.

  2. Recall the Fundamental Trigonometric Identity, which states that sin⁡2(x)+cos⁡2(x)=1\sin^2(x) + \cos^2(x) = 1. By observing that sin⁡3(x)=sin⁡(x)⋅sin⁡2(x)\sin^3(x) = \sin(x) \cdot \sin^2(x), use the Fundamental Trigonometric Identity to rewrite the integrand as the product of sin⁡(x)\sin(x) with another function.

  3. Explain why the substitution u=cos⁡(x)u = \cos(x) now provides a possible way to evaluate the integral i…

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.