Back to Geometric sums

Activity 8.3.4

Avg difficulty 2.5

Consider the function f(x)=11−xf(x) = \frac{1}{1-x}. Find the degree nn Taylor polynomial approximation centered at a=0a = 0 for ff.

  1. To begin finding Tn(x)T_n(x), do the usual work of computing the various derivatives of ff and their respective values at a=0a = 0; note that it's helpful to view f(x)f(x) in the form f(x)=(1−x)−1f(x) = (1-x)^{-1} so that we can easily compute the derivatives of ff using the chain rule. For instance, f′(x)=(−1)(1−x)−2(−1)\begin{gathered} f'(x) = (-1)(1-x)^{-2}(-1) \end{gathered} where the first “−1-1” arises from the power rule, while the second “−1-1” results from the chain rule, since ddx[1−x]=−1\frac{d}{dx}[1-x] = -1. In order to see key patterns that arise, it's helpful not to combine the products of numbers that arise in the various derivatives. Record the first five derivatives of f(x)f(x) in the spaces provided below. f(x)=11−x=(1−x)−1f′(x)=(−1)(1−x)−2(−1)f′′(x)=‾f′′′(x)=‾f(4)(x)=‾f(5)(x)=‾\begin{aligned} f(x) &= \frac{1}{1-x} = (1-x)^{-1} \\ f'(x) &= (-1)(1-x)^{-2}(-1) \\ f''(x) &= \underline{\hspace{2em}} \\ f'''(x) &= \underline{\hspace{2em}} \\ f^{(4)}(x) &= \underline{\hspace{2em}} \\ f^{(5)}(x) &= \underline{\hspace{2em}} \end{aligned}

  2. Next, evaluate the derivatives you determined in (a) at a=0a = 0 and use these to find the values of the coefficients of the Taylor polynomial centered at a=0a = 0. Record your work in the blank spaces provided. k=0f(0)=11−0=1c0=f(0)=1k=1f′(0)=(−1)(1−0)2⋅(−1)=1c1=f′(0)1!=11!=1k=‾f′′(0)=‾c2=f′′(0)2!=‾k=‾f′′′(0)=‾c3=‾k=‾f(4)(0)=‾c4=‾k=‾f(5)(0)=‾c5=‾\begin{aligned} k &= 0 & f(0) &= \frac{1}{1-0} = 1 & c_0 &= f(0) = 1 \\ k &= 1 & f'(0) &= \frac{(-1)}{(1-0)^{2}} \cdot (-1) = 1 & c_1 &= \frac{f'(0)}{1!} = \frac{1}{1!} = 1 \\ k &= \underline{\hspace{2em}} & f''(0) &= \underline{\hspace{2em}} & c_2 &= \frac{f''(0)}{2!} = \underline{\hspace{2em}} \\ k &= \underline{\hspace{2em}} & f'''(0) &= \underline{\hspace{2em}} & c_3 &= \underline{\hspace{2em}} \\ k &= \underline{\hspace{2em}} & f^{(4)}(0) &= \underline{\hspace{2em}} & c_4 &= \underline{\hspace{2em}} \\ k &= \underline{\hspace{2em}} & f^{(5)}(0) &= \underline{\hspace{2em}} & c_5 &= \underline{\hspace{2em}} \end{aligned}

  3. What pattern do you observe in the value of ckc_k? State the degree 55 Taylor polynomial, T5(x)T_5(x), as well as the formula you expect for the general degree nn Taylor polynomial, Tn(x)T_n(x).

  4. By identifying the value of rr, explain why the degree nn Taylor polynomial Tn(x)T_n(x) can be thought of as a finite geometric series.

  5. What is the Taylor series centered at a=0a = 0 for f(x)=11−xf(x) = \frac{1}{1-x}? (As we will see in the next section, the “Taylor series” of a function is the infinite series that results by simply extending the Taylor polynomials indefinitely.)

Boelkins, Active Calculus, §8.3 Geometric sums, Activity 8.3.4

AI Tutor

Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.