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Geometric sums

A closed form for a finite sum with constant ratio, the condition under which letting its terms run forever still gives a finite value, and the link back to polynomial approximation.

Active Calculus, Geometric sums

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4 exercises

Activity 8.3.3

For each of the following infinite geometric series, determine the values of aa and rr, compute the partial sums S5S_{5} and S10S_{10} exactly (writing each as a fraction), and if the infinite geometric series converges, find its value.

  1. 1+13+19+127+⋯1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \cdots

  2. 4−2+1−12+14−⋯4 - 2 + 1 - \frac{1}{2} + \frac{1}{4} - \cdots

  3. 2+83+329+12827+⋯2 + \frac{8}{3} + \frac{32}{9} + \frac{128}{27} + \cdots

  4. ∑k=0∞5⋅(34)k\sum_{k = 0}^{\infty} 5 \cdot \left( \frac{3}{4} \right)^k

  5. ∑k=1∞−2⋅(−23)k\sum_{k = 1}^{\infty} -2 \cdot \left( -\frac{2}{3} \right)^k

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Activity 8.3.4

Consider the function f(x)=11−xf(x) = \frac{1}{1-x}. Find the degree nn Taylor polynomial approximation centered at a=0a = 0 for ff.

  1. To begin finding Tn(x)T_n(x), do the usual work of computing the various derivatives of ff and their respective values at a=0a = 0; note that it's helpful to view f(x)f(x) in the form f(x)=(1−x)−1f(x) = (1-x)^{-1} so that we can easily compute the derivatives of ff using the chain rule. For instance, where the first “−1-1” arises from the power rule, while th…

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Exercise 7

In Equation, we learned that for an infinite geometric series , if ∣r∣<1|r| \lt 1, then . This result provides a quick way to determine the value of an infinite geometric series that converges.

In this exercise, we explore why the infinite geometric series fails to converge when r=1r = 1, r=−1r = -1, and ∣r∣>1|r|>1.

  1. If we consider the finite geometric series that results when a=1a = 1 and r=1r = 1, we get the sum , where there are nn terms in the sum.

    1. …

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Exercise 8

Suppose you drop a golf ball onto a hard surface from a height hh. The collision with the ground causes the ball to lose energy and so it will not bounce back to its original height. The ball will then fall again to the ground, bounce back up, and continue. Assume that at each bounce the ball rises back to a height 34\frac{3}{4} of the height from which it dropped. Let hnh_n be the height of the ball on the nnth bo…

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.