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Activity 8.4.3

Avg difficulty 2.5

Let f(x)=exf(x) = e^x. Our goal is to understand why the Taylor series for f(x)f(x) converges for every real number xx and see that the Taylor series converges to exe^x.

  1. For f(x)=exf(x) = e^x, explain why f(k)(0)=1f^{(k)}(0) = 1 for every natural number kk.

  2. State the Taylor series, Tf(x)T_f(x) centered at a=0a = 0 for f(x)=exf(x) = e^x. Write Tf(x)T_f(x) in both sigma notation and as an expanded sum.

  3. Let rn(x)r_n(x) be the ratio of the (n+1)st(n+1)^{\text{st}} term to the nthn^{\text{th}} term of Tf(x)T_f(x). Find the simplest expression you can for rn(x)r_n(x).

  4. Let r(x)=lim⁡n→∞rn(x)r(x) = \lim_{n \to \infty} r_n(x). Evaluate this limit, and then apply the Ratio Test to say what you can conclude about the xx-values for which Tf(x)T_f(x) converges.

  5. Use a computational device to graph f(x)=exf(x) = e^x, T10(x)T_{10}(x), and T20(x)T_{20}(x) on the same axes. What do you observe?

Boelkins, Active Calculus, §8.4 Taylor series, Activity 8.4.3

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.