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Exercise 8

Avg difficulty 2.5

The examples we have considered so far in this section have all been for Taylor polynomials and series centered at 0, but Taylor polynomials and series can be centered at any value of aa.

  1. Let f(x)=cos⁡(x)f(x) = \cos(x). Find the Taylor polynomials up through order four of ff centered at a=π2a = \frac{\pi}{2}. Then find the Taylor series for f(x)f(x) centered at a=π2a = \frac{\pi}{2}. Why is the result not surprising?

  2. Let f(x)=11+x=(1+x)−1f(x) = \frac{1}{1+x} = (1+x)^{-1}. Find the Taylor polynomials up through order four of ff centered at a=1a = 1. Then find the Taylor series for f(x)f(x) centered at a=1a = 1.

Boelkins, Active Calculus, §8.4 Taylor series, Exercise 8

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.