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Exercise 21

Avg difficulty 2.5

One of the properties of the cross product is that (u⃗+v⃗)×w⃗=(u⃗×w⃗)+(v⃗×w⃗)(\vu+\vv) \times \vw = (\vu \times \vw) + (\vv \times \vw). That is, the cross product distributes over vector addition on the right. Here we investigate whether the cross product distributes over vector addition on the left.

  1. Let u⃗=⟨1,2,−1⟩\vu = \langle 1,2,-1 \rangle, v⃗=⟨4,−3,6⟩\vv = \langle 4,-3,6 \rangle, and w⃗=⟨4,7,2⟩\vw = \langle 4,7,2 \rangle. Calculate u⃗×(v⃗+w⃗)   and   (u⃗×v⃗)+(u⃗×w⃗).\begin{gathered} \vu \times (\vv + \vw) \ \ \text{ and } \ \ (\vu \times \vv) + (\vu \times \vw). \end{gathered} What do you notice?

  2. Use the properties of the cross product to show that in general x⃗×(y⃗+z⃗)=(x⃗×y⃗)+(x⃗×z⃗)\begin{gathered} \vx \times (\vy + \vz) = (\vx \times \vy) + (\vx \times \vz) \end{gathered} for any vectors x⃗\vx, y⃗\vy, and z⃗\vz in R3\R^3.

Long, Keller & Schlicker, Active Calculus Multivariable, §9.5 The Cross Product, Exercise 21

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.