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Activity 9.6.2

Avg difficulty 2.5

Let P1=(1,2,−1)P_1 = (1,2,-1) and P2=(−2,1,−2)P_2 = (-2,1,-2) and let L\mathcal{L} be the line in R3\R^3 through P1P_1 and P2P_2. Note that Figure shows a similar example of a line in 3D defined by two points.

  1. Find a direction vector for the line L\mathcal{L}.

  2. Find a vector equation of L\mathcal{L} in the form r⃗(t)=r⃗0+tv⃗\vr(t) = \vr_0 + t\vv.

  3. Consider the vector equation s⃗(t)=⟨−5,0,−3⟩+t⟨6,2,2⟩.\vs(t) = \langle -5, 0, -3 \rangle + t \langle 6, 2, 2 \rangle. What is the direction of the line given by s⃗(t)\vs(t)? Is this new line parallel to line L\mathcal{L}?

  4. Do r⃗(t)\vr(t) and s⃗(t)\vs(t) represent the same line, L\mathcal{L}? Write a couple of sentences to justify why you think r⃗(t)\vr(t) and s⃗(t)\vs(t) do or do not describe the same set of points.

Long, Keller & Schlicker, Active Calculus Multivariable, §9.6 Lines in Space, Activity 9.6.2

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.