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Exercise 19

Avg difficulty 2.5

It can be shown that the derivative formula for the function ff defined by f(x)=2x3+2x+13+5x2\fe{f}{x}=\frac{2x^3+2x+1}{3+5x^2} is f′(x)=10x4+8x2−10x+625x4+30x2+9\fe{\fd{f}}{x}=\frac{10x^4+8x^2-10x+6}{25x^4+30x^2+9}.

Determine the equation of the tangent line to ff at 11.

Simonds, Calculus Lab Manual, §3.5 Supplement, Exercise 19

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