Back to 2.5 Quadratic Equations

2.5 Exercise 81

Avg difficulty 2.5

Enter the expressions into your graphing utility and find the zeroes to the equation (the x-intercepts) by using 2nd CALC 2:zero. Recall finding zeroes will ask left bound (move your cursor to the left of the zero,enter), then right bound (move your cursor to the right of the zero,enter), then guess (move your cursor between the bounds near the zero, enter). Round your answers to the nearest thousandth.

To solve the quadratic equation x 2 +5x−7=4, x^{2} + 5 x - 7 = 4 , we can graph these two equations

Y 1 = x 2 +5x−7 Y 2 =4 \begin{matrix} \\ \begin{matrix}\text{Y}_{1} = x^{2} + 5 x - 7 \\ \text{Y}_{2} = 4\end{matrix}\end{matrix}

and find the points of intersection. Recall 2nd CALC 5:intersection. Do this and find the solutions to the nearest tenth.

OpenStax Algebra and Trigonometry 2e, 2.5 Quadratic Equations, exercise 81

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Adapted from College Algebra © 2021 Rice University. Licensed under CC BY 4.0. Sources: College Algebra 2e, Algebra and Trigonometry 2e, Precalculus 2e, College Algebra with Corequisite Support 2e. Imported at revision 4922e46.