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12.3 Exercise 24

Avg difficulty 2.5

Determine why the function f f is discontinuous at a given point a a on the graph. State which condition fails.

f( x )={ x 2 −9 x+3 , x<−3 x−9, x=−3 1 x , x>−3     a=−3 f \left(x\right) = \left\{\right. \begin{matrix}\frac{x^{2} - 9}{x + 3} , & x < - 3 \\ x - 9 , & x = - 3 \\ \frac{1}{x} , & x > - 3\end{matrix} \textrm{ }\textrm{ }\textrm{ }\textrm{ } a = - 3

OpenStax Precalculus 2e, 12.3 Continuity, exercise 24

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Adapted from College Algebra © 2021 Rice University. Licensed under CC BY 4.0. Sources: College Algebra 2e, Algebra and Trigonometry 2e, Precalculus 2e, College Algebra with Corequisite Support 2e. Imported at revision 4922e46.