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14.5 Exercise 3

Avg difficulty 2.5

Calculate the concentration of each species present in a 0.010-M solution of phthalic acid, C6H4(CO2H)2.
C6H4(CO2H)2(aq)+H2O(l)⇌H3O+(aq)+C6H4(CO2H)(CO2)−(aq)Ka =1.1×10−3 C6H4(CO2H)(CO2)–(aq)+H2O(l)⇌H3O+(aq)+C6H4(CO2)22−(aq)Ka=3.9×10−6\begin{matrix} \\ \text{C}_{6} \text{H}_{4} \left(\text{CO}_{2} \text{H}\right)_{2} \left(a q\right) + \text{H}_{2} \text{O} \left(l\right) \rightleftharpoons \text{H}_{3} \text{O}^{+} \left(a q\right) + \text{C}_{6} \text{H}_{4} \left(\text{CO}_{2} \text{H}\right) \left(\text{CO}_{2}\right)^{−} \left(a q\right) K_{\text{a}} = 1.1 \times 10^{−3} \\ \text{C}_{6} \text{H}_{4} \left(\text{CO}_{2} \text{H}\right) \left(\text{CO}_{2}\right) ^{–} \left(a q\right) + \text{H}_{2} \text{O} \left(l\right) \rightleftharpoons \text{H}_{3} \text{O}^{+} \left(a q\right) + \text{C}_{6} \text{H}_{4} \left(\text{CO}_{2}\right)_{2} ^{2−} \left(a q\right) K_{\text{a}} = 3.9 \times 10^{−6}\end{matrix}

OpenStax Chemistry 2e, 14.5 Polyprotic Acids, exercise 3

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.