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13.4 Exercise 35

Avg difficulty 2.5

The equilibrium constant (Kc) for this reaction is 5.0 at a given temperature.

CO(g)+H2O(g)⇌CO2(g)+H2(g)\text{CO} \left(g\right) + \text{H}_{2} \text{O} \left(g\right) \rightleftharpoons \text{CO}_{2} \left(g\right) + \text{H}_{2} \left(g\right)

(a) On analysis, an equilibrium mixture of the substances present at the given temperature was found to contain 0.20 mol of CO, 0.30 mol of water vapor, and 0.90 mol of H2 in a liter. How many moles of CO2 were there in the equilibrium mixture?

(b) Maintaining the same temperature, additional H2 was added to the system, and some water vapor was removed by drying. A new equilibrium mixture was thereby established containing 0.40 mol of CO, 0.30 mol of water vapor, and 1.2 mol of H2 in a liter. How many moles of CO2 were in the new equilibrium mixture? Compare this with the quantity in part (a), and discuss whether the second value is reasonable. Explain how it is possible for the water vapor concentration to be the same in the two equilibrium solutions even though some vapor was removed before the second equilibrium was established.

OpenStax Chemistry 2e, 13.4 Equilibrium Calculations, exercise 35

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.