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12.3 Exercise 8

Avg difficulty 2.5

The rate constant for the radioactive decay of 14C is 1.21 ×\times 10−4 year−1. The products of the decay are nitrogen atoms and electrons (beta particles):
614C⟶714N+e−_{6}^{14} \text{C} \rightarrow _{7}^{14} \text{N} + \text{e}^{-}
rate=k[614C]\text{rate} = k \left[_{6}^{14} \text{C}\right]

What is the instantaneous rate of production of N atoms in a sample with a carbon-14 content of 6.5 ×\times 10−9 M?

OpenStax Chemistry 2e, 12.3 Rate Laws, exercise 8

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.