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4.5 Exercise 16

Avg difficulty 2.5

How many milliliters of a 0.1500-M solution of KOH will be required to titrate 40.00 mL of a 0.0656-M solution of H3PO4?
H3PO4(aq)+2KOH(aq)⟶K2HPO4(aq)+2H2O(l)\text{H}_{3} \text{PO}_{4} \left(a q\right) + 2 \text{KOH} \left(a q\right) \rightarrow \text{K}_{2} \text{HPO}_{4} \left(a q\right) + 2 \text{H}_{2} \text{O} \left(l\right)

OpenStax Chemistry 2e, 4.5 Quantitative Chemical Analysis, exercise 16

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.