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16.4 Exercise 12

Avg difficulty 2.5

Calculate the equilibrium constant at 25 °C for each of the following reactions from the value of ΔG° given.

(a) O2(g)+2F2(g)⟶2OF2(g)ΔG°=−9.2 kJ\text{O}_{2} \left(g\right) + \text{2F}_{2} \left(g\right) \rightarrow \text{2OF}_{2} \left(g\right) \Delta G ° = −\text{9}.\text{2 kJ}

(b) I2(s)+Br2(l)⟶2IBr(g)ΔG°=7.3 kJ\text{I}_{2} \left(s\right) + \text{Br}_{2} \left(l\right) \rightarrow \text{2IBr} \left(g\right) \Delta G ° = \text{7}.\text{3 kJ}

(c) 2LiOH(s)+CO2(g)⟶Li2CO3(s)+H2O(g)ΔG°=−79 kJ\text{2LiOH} \left(s\right) + \text{CO}_{2} \left(g\right) \rightarrow \text{Li}_{2} \text{CO}_{3} \left(s\right) + \text{H}_{2} \text{O} \left(g\right) \Delta G ° = −\text{79 kJ}

(d) N2O3(g)⟶NO(g)+NO2(g)ΔG°=−1.6 kJ\text{N}_{2} \text{O}_{3} \left(g\right) \rightarrow \text{NO} \left(g\right) + \text{NO}_{2} \left(g\right) \Delta G ° = −\text{1}.\text{6 kJ}

(e) SnCl4(l)⟶SnCl4(l)ΔG°=8.0 kJ\text{SnCl}_{4} \left(l\right) \rightarrow \text{SnCl}_{4} \left(l\right) \Delta G ° = \text{8}.\text{0 kJ}

OpenStax Chemistry 2e, 16.4 Free Energy, exercise 12

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.