Back to Jordan Canonical Form

Exercise 3

Avg difficulty 3.0

Find the Jordan form from the given data.

  • The matrix TT is 5 ⁣× ⁣55\!\times\!5 with the single eigenvalue 33. The nullities of the powers are: T−3IT-3I has nullity two, (T−3I)2(T-3I)^{2} has nullity three, (T−3I)3(T-3I)^{3} has nullity four, and (T−3I)4(T-3I)^{4} has nullity five.

  • The matrix SS is 5 ⁣× ⁣55\!\times\!5 with two eigenvalues. For the eigenvalue 22 the nullities are: S−2IS-2I has nullity two, and (S−2I)2(S-2I)^{2} has nullity four. For the eigenvalue −1-1 the nullities are: S+1IS+1I has nullity one.

Hefferon, Linear Algebra, Similarity, Jordan Canonical Form, Exercise 3

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.