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Exercise 11.1.6

Avg difficulty 3.0

. In this exercise, we will work out the details of Example 11.7. We must show that HilbR\mathbf{Hilb}_{\mathbb{R}} is a vector space. We will do this by showing that it is a subspace of SeqR\mathbf{Seq}_{\mathbb{R}}. Further, we must show that the inner product is well-defined. This requires some knowledge of convergent series from calculus.

  1. Assume a=(a0,a1,…)a=(a_{0},a_{1},\ldots) and b=(b0,b1,…)b=(b_{0},b_{1},\ldots) are square summable sequences. Show that the series a0b0+a1b1+a2b2+…a_{0}b_{0}+a_{1}b_{1}+a_{2}b_{2}+\ldots converges to a real number. Hint: consider the series ∣a0b0∣+∣a1b2∣+…\left|a_{0}b_{0}\right|+\left|a_{1}b_{2}\right|+\ldots and use the Cauchy-Schwarz inequality and the absolute convergence test.

  2. Using the result of part (a), show that HilbR\mathbf{Hilb}_{\mathbb{R}} is a subspace of SeqR\mathbf{Seq}_{\mathbb{R}}.

  3. Show that the operation ⟨a,b⟩=a0b0+a1b1+a2b2+…\langle a,b\rangle=a_{0}b_{0}+a_{1}b_{1}+a_{2}b_{2}+\ldots is an inner product on HilbR\mathbf{Hilb}_{\mathbb{R}}.

Selinger, Matrix Theory and Linear Algebra, Inner product spaces, Real inner product spaces, Exercise 11.1.6

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Adapted from Matrix Theory and Linear Algebra © 2017–2026 Peter Selinger, Lyryx Learning, and Ken Kuttler. Licensed under CC BY 4.0. Source: Matrix Theory and Linear Algebra. Imported at revision d74bc3a.