Back to Matrix Theory and Linear Algebra

Real inner product spaces

Testing whether formulas like u^T A v define inner products, and computing inner products and norms of functions in the space C[0,1].

Matrix Theory and Linear Algebra, Real inner product spaces

Status
FlagsLoading your progress…

6 exercises

Exercise 11.1.1

For each matrix AA, determine whether the formula ⟨u,v⟩=uTAv\langle\mathbf{u},\mathbf{v}\rangle=\mathbf{u}^{T}A\mathbf{v} determines an inner product on R2\mathbb{R}^{2}.

3.0

Exercise 11.1.2

Consider the inner product space C[0,1]C[0,1] as in Example 11.5. Compute the following inner products:

3.0

Exercise 11.1.3

Consider the inner product space C[0,1]C[0,1] as in Example 11.5. Compute the following norms:

3.0

Exercise 11.1.4

For u,v\mathbf{u},\mathbf{v} vectors in R3\mathbb{R}^{3}, define the product u∗v=u1v1+2u2v2+3u3v3\mathbf{u}\ast\mathbf{v}=u_{1}v_{1}+2u_{2}v_{2}+3u_{3}v_{3}. Show that

Hint: first show that the operation ⟨u,v⟩=u∗v\langle\mathbf{u},\mathbf{v}\rangle=\mathbf{u}\ast\mathbf{v} is an inner product on R3\mathbb{R}^{3}, then use Proposition 11.13.

3.0

Exercise 11.1.5

In C[−1,1]C[-1,1], find (a) the angle between xx and x2x^{2}, (b) the angle between xx and x3x^{3}.

3.0

Exercise 11.1.6

. In this exercise, we will work out the details of Example 11.7. We must show that HilbR\mathbf{Hilb}_{\mathbb{R}} is a vector space. We will do this by showing that it is a subspace of SeqR\mathbf{Seq}_{\mathbb{R}}. Further, we must show that the inner product is well-defined. This requires some knowledge of convergent series from calculus.

  1. Assume a=(a0,a1,…)a=(a_{0},a_{1},\ldots) and b=(b0,b1,…)b=(b_{0},b_{1},\ldots) are square summable sequences. Show that the series a0b0+a1b1+a2b2+…a_{0}b_{0}+a_{1}b_{1}+a_{2}b_{2}+\ldots converges to a real number. Hint: consider…

3.0

Adapted from Matrix Theory and Linear Algebra © 2017–2026 Peter Selinger, Lyryx Learning, and Ken Kuttler. Licensed under CC BY 4.0. Source: Matrix Theory and Linear Algebra. Imported at revision d74bc3a.