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Exercise 6.2.2

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Assume that T:Rn→RmT:\mathbb{R}^{n}\rightarrow\mathbb{R}^{m} is a linear transformation, and that u1,…,un\mathbf{u}_{1},\ldots,\mathbf{u}_{n} is a basis of Rn\mathbb{R}^{n}. For all i=1,…,ni=1,\ldots,n, let vi=T(ui)\mathbf{v}_{i}=T(\mathbf{u}_{i}). Let AA be the matrix that has u1,…,un\mathbf{u}_{1},\ldots,\mathbf{u}_{n} as its columns, and let BB be the matrix that has v1,…,vn\mathbf{v}_{1},\ldots,\mathbf{v}_{n} as its columns. Show that AA is invertible and the matrix of TT is BA−1BA^{-1}.

Selinger, Matrix Theory and Linear Algebra, Linear transformations in Rn, The matrix of a linear transformation, Exercise 6.2.2

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Adapted from Matrix Theory and Linear Algebra © 2017–2026 Peter Selinger, Lyryx Learning, and Ken Kuttler. Licensed under CC BY 4.0. Source: Matrix Theory and Linear Algebra. Imported at revision d74bc3a.