Back to Orthogonal complements and the matrix transpose

Activity 6.2.2

Avg difficulty 2.5

Suppose that w1=[10−2]\wvec_1=\threevec10{-2} and w2=[11−1]\wvec_2=\threevec11{-1} form a basis for WW, a two-dimensional subspace of R3\real^3. We will find a description of the orthogonal complement W⊥W^\perp.

  1. Suppose that the vector x\xvec is orthogonal to w1\wvec_1. If we write x=[x1x2x3]\xvec=\threevec{x_1}{x_2}{x_3}, use the fact that w1⋅x=0\wvec_1\cdot\xvec = 0 to write a linear equation for x1x_1, x2x_2, and x3x_3.

  2. Suppose that x\xvec is also orthogonal to w2\wvec_2. In the same way, write a linear equation for x1x_1, x2x_2, and x3x_3 that arises from the fact that w2⋅x=0\wvec_2\cdot\xvec = 0.

  3. If x\xvec is orthogonal to both w1\wvec_1 and w2\wvec_2, these two equations give us a linear system Bx=0B\xvec=\zerovec for some matrix BB. Identify the matrix BB and write a parametric description of the solution space to the equation Bx=0B\xvec = \zerovec.

  4. Since w1\wvec_1 and w2\wvec_2 form a basis for the two-dimensional subspace WW, any vector w\wvec in WW can be written as a linear combination w=c1w1+c2w2.\wvec = c_1\wvec_1 + c_2\wvec_2\text{.} If x\xvec is orthogonal to both w1\wvec_1 and w2\wvec_2, use the distributive property of dot products to explain why x\xvec is orthogonal to w\wvec.

  5. Give a basis for the orthogonal complement W⊥W^\perp and state the dimension dim⁡W⊥\dim W^\perp.

  6. Describe (W⊥)⊥(W^\perp)^\perp, the orthogonal complement of W⊥W^\perp.

Austin, Understanding Linear Algebra, §6.2 Orthogonal complements and the matrix transpose, Activity 6.2.2

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Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.