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The Multivariable Chain Rule

Differentiating compositions where each intermediate variable depends on others, organized by tree diagrams tracking every path of dependence.

Active Calculus Multivariable, The Multivariable Chain Rule

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5 exercises

Exercise 12

Find the indicated derivative. In each case, state the version of the Chain Rule that you are using.

  1. dfdt\frac{df}{dt}, if f(x,y)=2x2yf(x,y) = 2x^2y, x=cos⁡(t)x=\cos(t), and y=ln⁡(t)y=\ln(t).

  2. ∂f∂w\frac{\partial f}{\partial w}, if f(x,y)=2x2yf(x,y) = 2x^2y, x=w+z2x=w+z^2, and y=2z+1wy=\frac{2z+1}{w}

  3. ∂f∂v\frac{\partial f}{\partial v}, if f(x,y,z)=2x2y+z3f(x,y,z) = 2x^2y+z^3, x=u−v+2wx=u-v+2w, y=w2v−u3y=w2^v-u^3, and z=u2−vz = u^2-v

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Exercise 13

Let z=u2−v2z = u^2 - v^2 and suppose that

  1. Find the values of uu and vv that correspond to x=0x=0 and y=2π/3y=2\pi/3.

  2. Use the Chain Rule to find the general partial derivatives and then determine both ∂z∂x∣(0,2π3)\frac{\partial z}{\partial x}\restrict{(0, \frac{2\pi}{3})}{} and ∂z∂y∣(0,2π3)\frac{\partial z}{\partial y}\restrict{(0, \frac{2\pi}{3})}{}

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Exercise 15

Suppose that the temperature on a metal plate is given by the function TT with where the temperature is measured in degrees Fahrenheit and xx and yy are each measured in feet. Now suppose that an ant is walking on the metal plate in such a way that it walks in a straight line from the point (1,4)(1,4) to the point (5,6)(5,6).

  1. Find parametric equations (x(t),y(t))(x(t),y(t)) for the ant's coordinates as it walks the line from (1,4)(1,4) to (5,6)(5,6).

  2. What c…

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Exercise 16

There are several proposed formulas to approximate the surface area of the human body. One model uses the formula where AA is the surface area in square meters, hh is the height in centimeters, and ww is the weight in kilograms.

Since a person's height hh and weight ww change over time hh and ww are functions of time tt. Let us think about what is happening to a child whose height is 6060 centimeters and wei…

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Exercise 17

Let z=f(x,y)=50−(x+1)2−(y+3)2z = f(x,y) = 50 - (x+1)^2 - (y+3)^2 and z=h(x,y)=24−2x−6yz = h(x,y) = 24 - 2x - 6y.

Suppose a person is walking on the surface z=f(x,y)z = f(x,y) in such a way that she walks the curve which is the intersection of ff and hh.

  1. Show that x(t)=4cos⁡(t)x(t) = 4 \cos(t) and y(t)=4sin⁡(t)y(t) = 4 \sin(t) is a parameterization of the “shadow” in the xyxy-plane of the curve that is the intersection of the graphs of ff and hh.

  2. Use the parameterization from part (a) to find the instantaneous rate at which her height is changing with respect to time at the ins…

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.