3.4 Graph Linear Inequalities in Two Variables

Solve: $4 x + 3 > 23$.
If you missed this problem, review the reference.

Translate: $8 > x > 3$.
If you missed this problem, review the reference.

Determine whether each ordered pair is a solution to the inequality $y > x - 3 :$

ⓐ $\left(0 , 0\right)$ ⓑ $\left(4 , 9\right)$ ⓒ $\left(−2 , 1\right)$ ⓓ $\left(−5 , −3\right)$ ⓔ $\left(5 , 1\right)$

Determine whether each ordered pair is a solution to the inequality $y < x + 1 :$

ⓐ $\left(0 , 0\right)$ ⓑ $\left(8 , 6\right)$ ⓒ $\left(−2 , −1\right)$ ⓓ $\left(3 , 4\right)$ ⓔ $\left(−1 , −4\right)$

Determine whether each ordered pair is a solution to the given inequality.

Determine whether each ordered pair is a solution to the inequality $y > x - 1 :$

ⓐ $\left(0 , 1\right)$
ⓑ $\left(−4 , −1\right)$
ⓒ $\left(4 , 2\right)$
ⓓ $\left(3 , 0\right)$
ⓔ $\left(−2 , −3\right)$

Determine whether each ordered pair is a solution to the given inequality.

Determine whether each ordered pair is a solution to the inequality $y < 3 x + 2 :$

ⓐ $\left(0 , 3\right)$
ⓑ $\left(−3 , −2\right)$
ⓒ $\left(−2 , 0\right)$
ⓓ $\left(0 , 0\right)$
ⓔ $\left(−1 , 4\right)$

Determine whether each ordered pair is a solution to the given inequality.

Determine whether each ordered pair is a solution to the inequality $3 x - 4 y > 4 :$

ⓐ $\left(5 , 1\right)$
ⓑ $\left(−2 , 6\right)$
ⓒ $\left(3 , 2\right)$
ⓓ $\left(10 , −5\right)$
ⓔ $\left(0 , 0\right)$

Lester thinks that the solution of any inequality with a $>$ sign is the region above the line and the solution of any inequality with a $<$ sign is the region below the line. Is Lester correct? Explain why or why not.