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4.3 Exercise 16

Avg difficulty 2.5

What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 43.88 mL of a 0.3842 M solution of Cu(NO3)2?
2Cu(NO3)2+4KI⟶2CuI+I2+4KNO32 \text{Cu} \left(\text{NO}_{3}\right)_{2} + 4 \text{KI} \rightarrow 2 \text{CuI} + \text{I}_{2} + 4 \text{KNO}_{3}

OpenStax Chemistry 2e, 4.3 Reaction Stoichiometry, exercise 16

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.