Back to 5.3 Enthalpy

5.3 Exercise 25

Avg difficulty 2.5

Calculate ΔH°\Delta H ° for the process
Sb(s)+52Cl2(g)⟶SbCl5(s)\text{Sb} \left(s\right) + \frac{5}{2} \text{Cl}_{2} \left(g\right) \rightarrow \text{SbCl}_{5} \left(s\right)

from the following information:
Sb(s)+32Cl2(g)⟶SbCl3(s)ΔH°=−314kJSbCl3(s)+Cl2(g)⟶SbCl5(s)ΔH°=−80kJ\begin{matrix} \\ \text{Sb} \left(s\right) + \frac{3}{2} \text{Cl}_{2} \left(g\right) \rightarrow \text{SbCl}_{3} \left(s\right) \Delta H ° = −314 \text{kJ} \\ \text{SbCl}_{3} \left(s\right) + \text{Cl}_{2} \left(g\right) \rightarrow \text{SbCl}_{5} \left(s\right) \Delta H ° = −80 \text{kJ}\end{matrix}

OpenStax Chemistry 2e, 5.3 Enthalpy, exercise 25

AI Tutor

Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.