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5.3 Exercise 27

Avg difficulty 2.5

Calculate ΔH for the process Hg2Cl2(s)⟶2Hg(l)+Cl2(g)\text{Hg}_{2} \text{Cl}_{2} \left(s\right) \rightarrow 2 \text{Hg} \left(l\right) + \text{Cl}_{2} \left(g\right)

from the following information:
Hg(l)+Cl2(g)⟶HgCl2(s)ΔH=−224kJHg(l)+HgCl2(s)⟶Hg2Cl2(s)ΔH=−41.2kJ\begin{matrix}\text{Hg} \left(l\right) + \text{Cl}_{2} \left(g\right) \rightarrow \text{HgCl}_{2} \left(s\right) \Delta H = −224 \text{kJ} \\ \text{Hg} \left(l\right) + \text{HgCl}_{2} \left(s\right) \rightarrow \text{Hg}_{2} \text{Cl}_{2} \left(s\right) \Delta H = −41.2 \text{kJ}\end{matrix}

OpenStax Chemistry 2e, 5.3 Enthalpy, exercise 27

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.