Back to Bases and coordinate systems

Activity 3.2.3

Avg difficulty 2.5

Let's begin with the basis B={v1,v2}\bcal = \{\vvec_1,\vvec_2\} of R2\real^2 where v1=[3−2],v2=[21]\vvec_1 = \twovec{3}{-2}, \vvec_2 = \twovec{2}{1}.

  1. If the coordinates of x\xvec in the basis B\bcal are {x}B=[−24]\coords{\xvec}{\bcal} = \twovec{-2}{4}, what is the vector x\xvec?

  2. If x=[35]\xvec = \twovec{3}{5}, find the coordinates of x\xvec in the basis B\bcal; that is, find {x}B\coords{\xvec}{\bcal}.

  3. Find a matrix AA such that, for any vector x\xvec, we have x=A{x}B\xvec = A\coords{\xvec}{\bcal}. Explain why this matrix is invertible.

  4. Using what you found in the previous part, find a matrix BB such that, for any vector x\xvec, we have {x}B=Bx\coords{\xvec}{\bcal} = B\xvec. What is the relationship between the two matrices AA and BB? Explain why this relationship holds.

  5. Suppose we consider the standard basis E={e1,e2}\ecal = \{\evec_1,\evec_2\}. What is the relationship between x\xvec and {x}E\coords{\xvec}{\ecal}?

  6. Suppose we also consider the basis C={[12],[−21]}\ccal = \left\{\twovec{1}{2}, \twovec{-2}{1}\right\}. Find a matrix CC that converts coordinates in the basis C\ccal into coordinates in the basis B\bcal; that is, {x}B=C{x}C\coords{\xvec}{\bcal} = C \coords{\xvec}{\ccal}. You may wish to think about converting coordinates from the basis C\ccal into the standard coordinate system and then into the basis B\bcal.

Austin, Understanding Linear Algebra, §3.2 Bases and coordinate systems, Activity 3.2.3

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Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.