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Exercise 2

Avg difficulty 2.5

Consider vectors v1=[12],v2=[1−3]w1=[23],w2=[−1−2].\begin{aligned} \vvec_1=\twovec{1}{2}, & \vvec_2=\twovec{1}{-3} \\ \wvec_1=\twovec{2}{3}, & \wvec_2=\twovec{-1}{-2} \text{.} \\ \end{aligned} and let B={v1,v2}\bcal = \{\vvec_1,\vvec_2\} and C={w1,w2}\ccal = \{\wvec_1,\wvec_2\}.

  1. Explain why B\bcal and C\ccal are both bases of R2\real^2.

  2. If x=[5−3]\xvec = \twovec{5}{-3}, find {x}B\coords{\xvec}{\bcal} and {x}C\coords{\xvec}{\ccal}.

  3. If {x}B=[2−4]\coords{\xvec}{\bcal}=\twovec{2}{-4}, find x\xvec and {x}C\coords{\xvec}{\ccal}.

  4. If {x}C=[−32]\coords{\xvec}{\ccal}=\twovec{-3}{2}, find x\xvec and {x}B\coords{\xvec}{\bcal}.

  5. Find a matrix QQ such that {x}B=Q{x}C\coords{\xvec}{\bcal} = Q\coords{\xvec}{\ccal}.

Austin, Understanding Linear Algebra, §3.2 Bases and coordinate systems, Exercise 2

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Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.