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8.4 Molecular Orbital Theory

Atomic orbitals combined into bonding and antibonding levels, filling diagrams for second-row diatomics, bond order, and magnetic behavior.

Chemistry 2e, 8.4 Molecular Orbital Theory

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9 exercises

8.4 Exercise 2

How are the following similar, and how do they differ?

(a) σ molecular orbitals and π molecular orbitals

(b) ψ for an atomic orbital and ψ for a molecular orbital

(c) bonding orbitals and antibonding orbitals

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8.4 Exercise 4

Can a molecule with an odd number of electrons ever be diamagnetic? Explain why or why not.

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8.4 Exercise 6

Why are bonding molecular orbitals lower in energy than the parent atomic orbitals?

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8.4 Exercise 8

Explain why an electron in the bonding molecular orbital in the H2 molecule has a lower energy than an electron in the 1s atomic orbital of either of the separated hydrogen atoms.

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8.4 Exercise 10

Determine the bond order of each member of the following groups, and determine which member of each group is predicted by the molecular orbital model to have the strongest bond.

(a) H2, H2+,\text{H}_{2} ^{+} , H2−\text{H}_{2} ^{−}

(b) O2, O22+,\text{O}_{2} ^{\text{2}+} , O22−\text{O}_{2} ^{\text{2}−}

(c) Li2, Be2+,\text{Be}_{2} ^{+} , Be2

(d) F2, F2+,\text{F}_{2} ^{+} , F2−\text{F}_{2} ^{−}

(e) N2, N2+,\text{N}_{2} ^{+} , N2−\text{N}_{2} ^{−}

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8.4 Exercise 12

Compare the atomic and molecular orbital diagrams to identify the member of each of the following pairs that has the highest first ionization energy (the most tightly bound electron) in the gas phase:

(a) H and H2

(b) N and N2

(c) O and O2

(d) C and C2

(e) B and B2

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8.4 Exercise 14

A friend tells you that the 2s orbital for fluorine starts off at a much lower energy than the 2s orbital for lithium, so the resulting σ2s molecular orbital in F2 is more stable than in Li2. Do you agree?

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8.4 Exercise 16

What charge would be needed on F2 to generate an ion with a bond order of 2?

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8.4 Exercise 18

Explain why N22+\text{N}_{2} ^{\text{2}+} is diamagnetic, while O24+,\text{O}_{2} ^{\text{4}+} , which has the same number of valence electrons, is paramagnetic.

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Adapted from General Chemistry © 2019 Rice University. Licensed under CC BY 4.0. Sources: Chemistry 2e, Chemistry: Atoms First 2e. Imported at revision 32c7196.