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Invertibility

When a square matrix has an inverse, the 2x2 formula for it, solving Ax = b in a single step, and the conditions equivalent to invertibility.

Understanding Linear Algebra, Invertibility

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15 exercises

Activity 3.1.2

This activity demonstrates a procedure for finding the inverse of a matrix AA.

  1. Suppose that A=[3−21−1]A = \begin{bmatrix} 3 & -2 \\ 1 & -1 \\ \end{bmatrix}. To find an inverse BB, we write its columns as B=[b1b2]B = \begin{bmatrix}\bvec_1 & \bvec_2 \end{bmatrix} and require that In other words, we can find the columns of BB by solving the equations Solve these equations to find b1\bvec_1 and b2\bvec_2. Then write the matrix BB and verify that AB=IAB=I. This is enough for us to conclude that BB is the inverse of AA.

  2. Find the product BABA and expl…

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Activity 3.1.3

We'll begin by considering the square matrix

  1. Describe the solution space to the equation Ax=[343]A\xvec = \threevec343 by augmenting AA and finding the reduced row echelon form.

  2. Using this proposition, explain why AA is invertible and find its inverse.

  3. Now use the inverse to solve the equation Ax=[343]A\xvec = \threevec343 and verify that your result agrees with what you found in part a.

  4. If you have defined a matrix B in Sage, you can find it's inverse as B…

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Activity 3.1.4

This activity explores how the row operations of scaling, interchange, and replacement can be performed using matrix multiplication.

As an example, we consider the matrix and apply a replacement operation that multiplies the first row by −2-2 and adds it to the second row. Rather than performing this operation in the usual way, we construct a new matrix by applying the desired replacement operation t…

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Exercise 1

Consider the matrix .

  1. Explain why AA has an inverse.

  2. Find the inverse of AA by augmenting by the identity II to form [AI]\left[\begin{array}{r|r}A & I \end{array}\right].

  3. Use your inverse to solve the equation Ax=[32−3−1]A\xvec = \fourvec{3}{2}{-3}{-1}.

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Exercise 2

In this exercise, we will consider 2×22\times 2 matrices as defining matrix transformations.

  1. Write the matrix AA that performs a 45∘45^\circ rotation. What geometric operation undoes this rotation? Find the matrix that perform this operation and verify that it is A−1A^{-1}.

  2. Write the matrix AA that performs a 180∘180^\circ rotation. Verify that A2=IA^2 = I so that A−1=AA^{-1} = A, and explain geometrically why this is the case.

  3. Find three more matrices AA that satisf…

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Exercise 3

Inverses for certain types of matrices can be found in a relatively straightforward fashion.

  1. The matrix D=[2000−1000−4]D=\begin{bmatrix} 2 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -4 \\ \end{bmatrix} is called diagonal since the only nonzero entries are on the diagonal of the matrix.

    1. Find D−1D^{-1} by augmenting DD by the identity and finding its reduced row echelon form.

    2. Under what conditions is a diagonal matrix invertible?

    3. Explain why the inverse of a diagonal matrix is also diagonal and explain the…

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Exercise 4

Our definition of an invertible matrix requires that AA be a square n×nn\times n matrix. Let's examine what happens when AA is not square. For instance, suppose that .

  1. Verify that BA=I2BA = I_2. In this case, we say that BB is a left inverse of AA.

  2. If AA has a left inverse BB, we can still use it to find solutions to linear equations. If we know there is a solution to the equation Ax=bA\xvec = \bvec, we can multiply both sides of the equation b…

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Exercise 5

If a matrix AA is invertible, there is a sequence of row operations that transforms AA into the identity matrix II. We have seen that every row operation can be performed by matrix multiplication. If the jthj^{th} step in the Gaussian elimination process is performed by multiplying by EjE_j, then we have , which means that . For each of the following matrices, find a sequence of row operations that transforms th…

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Exercise 6

Suppose that AA is an n×nn\times n matrix.

  1. Suppose that A2=AAA^2 = AA is invertible with inverse BB. This means that A2B=AAB=IA^2B = AAB = I. Explain why AA must be invertible with inverse ABAB.

  2. Suppose that A100A^{100} is invertible with inverse BB. Explain why AA is invertible. What is A−1A^{-1} in terms of AA and BB?

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Exercise 7

Determine whether the following statements are true or false and explain your reasoning.

  1. If AA is invertible, then the columns of AA are linearly independent.

  2. If AA is a square matrix whose diagonal entries are all nonzero, then AA is invertible.

  3. If AA is an invertible n×nn\times n matrix, then span of the columns of AA is Rn\real^n.

  4. If AA is invertible, then there is a nonzero solution to the homogeneous equation Ax=0A\xvec = \zerovec.

  5. If AA is an…

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Exercise 8

Provide a justification for your response to the following questions.

  1. Suppose that AA is a square matrix with two identical columns. Can AA be invertible?

  2. Suppose that AA is a square matrix with two identical rows. Can AA be invertible?

  3. Suppose that AA is an invertible matrix and that AB=ACAB = AC. Can you conclude that B=CB = C?

  4. Suppose that AA is an invertible n×nn\times n matrix. What can you say about the span of the columns of A−1A^{-1}?

  5. S…

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Exercise 9

Suppose that we start with the 3×33\times3 matrix AA, perform the following sequence of row operations:

  1. Multiply row 1 by -2 and add to row 2.

  2. Multiply row 1 by 4 and add to row 3.

  3. Scale row 2 by 1/21/2.

  4. Multiply row 2 by -1 and add to row 3,

and arrive at the upper triangular matrix

  1. Write the matrices E1E_1, E2E_2, E3E_3, and E4E_4 that perform the four row operations.

  2. Find the matrix E=E4E3E2E1E = E_4E_3E_2E_1.

  3. We then have E4E3E2E1A=EA=UE_4E_3E_2E_1 A = EA = U. Now that we have the matrix EE,…

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Exercise 10

We say that two square matrices AA and BB are similar if there is an invertible matrix PP such that B=PAP−1B = PAP^{-1}.

  1. If AA and BB are similar, explain why A2A^2 and B2B^2 are similar as well. In particular, if B=PAP−1B = PAP^{-1}, explain why B2=PA2P−1B^2 = PA^2P^{-1}.

  2. If AA and BB are similar and AA is invertible, explain why BB is also invertible.

  3. If AA and BB are similar and both are invertible, explain why A−1A^{-1} and B−1B^{-1} are similar.

  4. If AA is similar to BB and BB is similar to CC,…

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Exercise 11

Suppose that AA and BB are two n×nn\times n matrices and that ABAB is invertible. We would like to explain why both AA and BB are invertible.

  1. We first explain why BB is invertible.

    1. Since ABAB is invertible, explain why any solution to the homogeneous equation ABx=0AB\xvec = \zerovec is x=0\xvec=\zerovec.

    2. Use this fact to explain why any solution to Bx=0B\xvec = \zerovec must be x=0\xvec=\zerovec.

    3. Explain why BB must be invertible.

  2. Now we explain why AA is invertible.

    1. Since ABAB is invertible, explain w…

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Exercise 12

We defined an n×nn\times n matrix to be invertible if there is a matrix BB such that AB=InAB=I_n. In this exercise, we will explain why it is also true that BA=IBA = I, which is the statement of this proposition. This means that, if B=A−1B=A^{-1}, then A=B−1A = B^{-1}.

  1. Suppose that x\xvec is an nn-dimensional vector. Since AB=IAB=I, explain why ABx=xAB\xvec = \xvec and use this to explain why the only vector for which Bx=0B\xvec = \zerovec is x=0\xvec = \zerovec.

  2. Explain why this implies that BB must be invertible. We will c…

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Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.